您要查找的是不是：
- covariant functor 协变函子
- left exact covariant functor 左正合共变函子
- Functor returns the marked price as output. 仿函数就返回标签价格作为输出。
- How to use local type as functor? 似乎不能接受局部类型。难道没有变通方法？
- Throws : If the hash functor throws. 抛出:如果散列函数抛出。
- Covariant return types are now supported. 现支持协变返回类型。
- Throws : If the comparison functor throws. 抛出:如果比较函数抛出。
- Language and the society are covariant. 语言与社会是一种共变关系。
- Method uses two constructs provided by the Apache Functor library. 方法使用由Apache Functor库提供的两个结构。
- Functor takes a binary function and two unary functions as input. 仿函数取一个二元函数和两个一元函数作为输入。
- Expressing, exhibiting, or relating to covariant theory. 协变式的表达协变理论的，显示协变理论的，与协变理论有关的
- You used this functor twice for binary composition in Listing 4. 在清单4中对二元合成使用这个仿函数两次。
- Every vector can be resolved into covariant or into contravariant components. 每个矢量都可以分解成协变分量或逆变分量。
- The proof shows that any functor which is a left adjoint is right exact. 该证明指出，任一函子，如果是一个左伴随，就右正合。
- A function or functor, as usual, may be attached to the symbol table. 通常，可以将一个函数或仿函数附加至符号表。
- Since it does not take in any K, it can safely be declared to be covariant on K. 因为它没有传入任何K类型的对象，它能安全地声明为对于K可协变的。
- This decomposition may give another definition of high order tensor's covariant derivative. 这种分解可以给出高阶张量协变导数的另一种定义。
- The discussion from here forward will incorporate examples based on the Apache Commons Functor library. 从这以后的讨论将结合基于Apache Commons Functor库的例子。
- Functor passing in the outcome of the previous evaluation as parameter to this one. 仿函数,然后用前一个计算的输出作为参数计算。
- ANCOVAs were conducted to analyze the performance scores with pretest as the covariant. 研究结果发现：(1)在事实性问题的学习成效上，摘要策略对学习成效没有显著的影响；
